N^2+4n-5/n2+7n+35 - solution

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Solution for N^2+4n-5/n2+7n+35 equation:

D( x )

n^2 = 0

n^2 = 0

n^2 = 0

n^2 = 0

x naleu017Cy do R

x belongs to the empty set

N^2+4*n+7*n-(5/(n^2))+35 = 0

x belongs to the empty set

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